Hudson Mindell Kitchell (1862-1944) - New Jersey, New York, Rhode Island
Hudson Mindell Kitchell was born in Madison, New Jersey in November 1862. Little is known about the artist's childhood and formal art education. Historical records indicate that Kitchell married Lydia Pierce of Rhode Island in September 1880, when he was just seventeen. The young couple had a son, Percy, four years later. In the early part of his career, Kitchell worked as a contract painter in a Ne (showing 500 of 10114 characters). |
|
|
|
|
|
|
Subscriber Members, please Log On for artist biographies and for all services.
| If you are not currently a member, please See Details about membership, which includes biography access, auction records, and many other features available to our day, month, or yearly Subscriber Members! | | This artist's biography is accessible freely to anyone every Friday. |
|
|